In the original 1928 paper (pdf) the Dirac equation appears on page 615 in equation (9) as
$$ [p_0+\rho_1\left(\boldsymbol{\sigma},\boldsymbol{p}\right)+\rho_3mc]\psi=0\qquad(1) $$
Using the definitions
$$ p_0=i\hbar\frac{\partial}{c\partial t};\quad\boldsymbol{p}=-i\hbar\boldsymbol{\nabla} $$
from pages 613 and 611 as well expressing the matrices given at the bottom of page 614 in modern notation
$$ \rho_1\rightarrow\gamma_5;\quad\boldsymbol{\sigma}\rightarrow\boldsymbol{\Sigma};\quad\rho_3\rightarrow\beta $$
and finally multiplying through with the speed of light $c$, we obtain the equation
$$ [i\hbar\frac{\partial}{\partial t}+c(\boldsymbol{\alpha}\cdot\boldsymbol{p})+\beta mc^2]\psi=0 $$
However, this is not how the Dirac equation is written today; the term with the time derivative has the opposite sign !
The form (1) is also found in the third edition (1947) of Dirac's book The Principles of Quantum Mechanics (see eq (8) on page 256).
In the fourth edition (1958), however, in equation (10) on page 257, we find
$$ [p_0-\rho_1\left(\boldsymbol{\sigma},\boldsymbol{p}\right)-\rho_3mc]\psi=0\qquad(2) $$
that translates into the form we know today. Basically, eq (2) is obtained from eq (1) by changing the sign of time.
Do we know why Dirac modified his equation in this way ?