See my two 7-Feb-2022 comments above. Given how long it's likely to be before I complete this project and the very incomplete details about the result one can find (internet or publications), I thought it might be best to offer at least some of the "annotated chronologically-ordered bibliography" now, and revise it as appropriate at some later time. What follows does not include some preliminary comments I intended to make, because they are not in very good form now (mostly just notes to myself about certain things), and does not go up to the late 1910s (after WW I is where a natural stopping point seems to be, but I'm stopping well before that for now).
Regarding my italization and other conventions when giving excerpts from publications (includes translations of excerpts), see Conventions near the beginning of this answer.
[1] Augustin Louis Cauchy (1789-1857), Résumés Analytiques [Analytical Summaries], l'Académie des sciences de Turin [Accademia delle Scienze di Torino; Academy of Sciences of Turin] (Italy), 1833, 166 pages.
Reprinted on pp. 7-182 in Cauchy, Œuvres Complètes, série 2, tome 10, Gauthier-Villars et fils, 1895, 184 pages. A table of contents, not in the 1833 publication, is given on pp. 183-184 of the 1895 publication. The following is from Grattan-Guinness (1990, Convolutions in French Mathematics, 1800-1840, Volume II, p. 1228): Cauchy gave his own vision of mathematical analysis further airing when in 1833 he published his Résumés analytiques in Turin (1833c), a 166-page summary of the Cours d'analyse and certain related papers. Many of the basic definitions and results were repeated more or less verbatim: not only his definition of infinitesimals but also Theorem 1136.1 [G-G's numbering; appears on p. 721] on the continuity of the sum-function, convergence tests, series expansions of basic functions, trigonometry, complex variables, de Moivre's theorem, and so on. In his foreword he promised a series of livaisons [= installments] to continue upon this book, but they did not appear. The earliest published observation I know of that the sum of an infinite series can be affected by a rearrangement of its terms appears near the beginning of §8. Des séries doubles ou multiples. Nombres de Bernoulli (pp. 56-68). Specifically, Cauchy gives an example of a rearrangement of the alternating harmonic series $1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \cdots$ that results in a series that does not converge.
(from middle of p. 58 to top p. 59) [translated from French] But if, instead of adding the terms to each other, $$\mp \, \frac{1}{n+1}\,, \;\;\; \pm \, \frac{1}{n+2}\,, \;\;\; \mp \, \frac{1}{n+3}\,, \;\;\; \text{etc.} \;\;\; .....$$ taken in the order they are located, we change this order by choosing among the terms assigned the same sign, for example, the following $$\pm \, \frac{1}{n+2}\,, \;\;\; \pm \, \frac{1}{n+4}\,, \;\;\; ..... \;\;\; \pm \, \frac{1}{n+2n} \; = \; \pm \, \frac{1}{3n}\,,$$ [then] the numerical value of the sum of these terms, as follows, $$\frac{1}{n+2} \; + \; \frac{1}{n+4} \; + \; ..... \; + \; \frac{1}{3n}$$ obviously exceeds the product $$n \times \frac{1}{3n} \; = \; \frac{1}{3}\,,$$ and ceases to be infinitely small for infinitely large values of $n.$ After this, Cauchy returns to discussing "multiple series" (double series, triple series, etc. whose terms are defined by the use of double subscripts, triple subscripts, etc.), saying that when all the terms are positive then, by a theorem previously stated, it follows that the convergence (and sum?) is not affected by various methods of adding the terms.
The rearrangement Cauchy briefly described has the form $1 - \frac{1}{2} + a_1 - a_2 + a_3 - \cdots + (-1)^{n+1}a_n + \cdots,$ where $a_1 = \frac{1}{3}$ and $a_2 = \frac{1}{4} + \frac{1}{6}$ and $a_3 = \frac{1}{5} + \frac{1}{7} + \frac{1}{9}$ and so on, where each $a_n$ represents a finite sequence of same-signed terms from the original sequence such that the ordering of these same-signed terms among themselves is not altered and where the number of these same-signed terms is such that this number times the absolute value of the last term included equals $\frac{1}{3}.$ For example, $a_4 = \frac{1}{8} + \cdots + \frac{1}{18}$ and $a_5 = \frac{1}{11} + \cdots + \frac{1}{27}.$ Note that $a_4$ includes $6$ terms and $6(\frac{1}{18}) = \frac{1}{3},$ while $a_5$ includes $9$ terms and $9(\frac{1}{27}) = \frac{1}{3}.$ By design, $a_n \geq \frac{1}{3}$ for each $n,$ so $1 - \frac{1}{2} + a_1 - a_2 + a_3 - \cdots + (-1)^{n+1}a_n + \cdots$ diverges by the $n$-term divergence test (the $n$th term doesn't approach zero). Thus, the sequence of partial sums of this series does not converge, and since this sequence of partial sums is a subsequence of the sequence of partial sums of the rearranged series, it follows that the rearranged series diverges.
(from pp. 157-158 of Bottazzini/Gray's 2013 Hidden Harmony ...) Cauchy taught in Turin from October 1832 to July 1833, when he was called to Prague to serve as a tutor to the son of the exiled king Charles X. In accordance with the title of his chair, he delivered introductory lectures of a philosophical-theological character (Cauchy 1888a). The essential content of his Turin lectures was published in the Résumés analytiques (Cauchy 1833b) which appeared in print when he was already living in Bohemia, and contain nothing new by comparison to his previous treatises. A vivid account of Cauchy's teaching was provided by Luigi Federico Menabrea.$^{text{38}}$ Not surprisingly, Cauchy's lectures [begin centered quote] were very confused, skipping suddenly from one idea to another, from one formula to the next, with no attempt to give a connection between them. His presentations were obscure clouds, illuminated from time to time by flashes of pure genius (quoted in Belhoste 1991, 156). [end centered quote] so much so that Menabrea was the only one to "see it through" out of some 30 students who initially enrolled in the course.
[2] Johann Peter Gustav Lejeune Dirichlet (1805-1859), Beweis des satzes, dafs [= dass] jede unbegrenzte arithmetische progression, deren erstes glied und differenz ganze zahlen ohne gemeinschaftlichen factor sind, unendlich viele primzahlen enthält [Proof of the theorem, that every unlimited arithmetic progression whose first member and difference are whole numbers without a common factor, contains infinitely many prime numbers], Abhandlungen der Königlichen Akademie der Wissenschaften zu Berlin. Mathematische, aus dem Jahre 1837 [for the year 1837], published in 1839, pp. 45-71.
Another digital copy is here Reprinted on pp. 315-345 of G. Lejeune Dirichlet's Werke, Volume 1, 1889. For an English translation by Ralf Stephan, see here. A statement appearing just above the first line of the paper says (translated): Read to the Akademie der Wissenschaften on 27 July 1837. Note: Page 71 is incorrectly labeled as "81". This typo has led to some incorrect "45-81" page ranges having been published: Joseph Dauben's 1979 book Georg Cantor ... (p. 368, line -6), Jesper Lützen's 1990 book Joseph Liouville ... (p. 824, line 12), Morris Kline's 1990 Volume 3 of Mathematical Thought ... (p. 830, footnote 35; p. 966, footnote 54), Bottazzini/Gray's 2013 Hidden Harmony ... (p. 782, 3rd item from top), versions 1 and 2 of Stephan's English translation (footnote on first page). Dirichlet makes some comments about the convergence of infinite series beginning near the bottom of p. 48 and continuing onto p. 49. What follows is excerpted from pp. 3-4 of version 2 (latest version; 24 November 2014) of Stephan's English translation: Before we go on it is necessary to state the reason for the condition made above, that $s>1$ should hold. We can convince ourselves of the necessity of this limitation if we respect the essential difference which exists between two kinds of infinite series. $[\cdots]$ So, for example, of the two series made from the same terms $$ 1 - \frac{1}{\sqrt{2}} + \frac{1}{\sqrt{3}} - \frac{1}{\sqrt{4}} + \frac{1}{\sqrt{5}} - \frac{1}{\sqrt{6}} + \cdots,$$ $$ 1 + \frac{1}{\sqrt{3}} - \frac{1}{\sqrt{2}} + \frac{1}{\sqrt{5}} + \frac{1}{\sqrt{7}} - \frac{1}{\sqrt{4}} + \cdots,$$ only the first converges while of the following $$ 1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \frac{1}{5} - \frac{1}{6} + \cdots,$$ $$ 1 + \frac{1}{3} - \frac{1}{2} + \frac{1}{5} + \frac{1}{7} - \frac{1}{4} + \cdots,$$ both converge, but with different sums. Our infinite series $L,$ as can be easily seen, belongs only then to the first of the classes $[\cdots]$ I cannot find any explicit mention of Cauchy in this paper.
[3] Dirichlet, Démonstration de cette proposition: toute progression arithmétique dont le premier terme et la raison sont des entiers sans diviseur commun, contient une infinité de nombres premiers [Proof of this proposition: every arithmetic progression such that the first term and common ratio are integers without common divisor, contains an infinity of prime numbers], Journal de Mathématiques Pures et Appliquées [= Liouville's Journal] (1) 4 (1839), 393-422.
A footnote (by Joseph Liouville, 1809-1882) at the bottom of p. 393 states that this is a translation by Olry Terquem (1782-1862) of Dirichlet's 1837 paper. Dirichlet's remarks about rearranging terms of an infinite sequence extend from the bottom of p. 396 to the middle of p. 397.
[3] Dirichlet, Recherches sur diverses applications de l'analyse infinitésimale à la théorie des nombres [Investigations on diverse applications of infinitesimal analysis to the theory of numbers], Journal für die Reine und Angewandte Mathematik 19 #4 (1839), 324-369.
Dirichlet gives 4 July 1839 (on p. 369) for the date of the paper's completion. Dirichlet makes some comments about the convergence of infinite series beginning on p. 329 (line -10) and continuing onto p. 330, where I believe Dirichlet discusses the fact that rearrangements of certain series can lead to different values. However, I do not see any specific examples given. It might be the case that a specific example is described verbally, though. I cannot find any explicit mention of Cauchy in this paper.
[4] Martin [Marcin, Martinus] Ohm (1792-1872), **De Nonnullis Seriebus Infinitis Summandis** [Concerning the Summation of Certain Infinite Series], Trowitzschii et Filii [Trowitzsch und Sohn; Trowitzsch and Son] (Berlin), 1839, 15 pages.
A 300+ page biography of Ohm was published in 1987, but I have not been able to examine it. This is a separately published booklet, written in Latin, that deals with the summation of certain rearrangements of the alternating harmonic series $1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \cdots.$ In §1 (p. 3) the alternating harmonic series is shown to have sum $\ln {2}.$ Ohm's verification consists of plugging $x=0$ into the Maclaurin series for $\ln (1+x).$ The remaining verifications are similar in that Ohm first obtains series expansions of certain rational functions and their natural logarithms. In §2 (pp. 3-6) the rearrangement in which $2$ positive terms are followed by $1$ negative term is shown to have sum $\frac{3}{2}\ln {2}.$ In §3 (pp. 6-7) the result for $1$ positive term followed by $2$ negative terms is shown to have sum $\frac{1}{2}\ln {2}.$ In §4 (pp. 7-8) the result for $3$ positive terms followed by $1$ negative term is shown to have sum $\frac{1}{2}\ln {3}.$ In §5 (pp. 8-9) the result for $3$ positive terms followed by $2$ negative terms is shown to have sum $\frac{1}{2}\ln 2 + \frac{1}{2}\ln {3}.$ In §6 (pp. 9-11) the result for $m$ positive terms followed by $1$ negative term is shown to have sum $\ln 2 + \frac{1}{2}\ln {m}.$ In §7 (pp. 11-12) the result for $1$ positive term followed by $n$ negative terms is shown to have sum $\ln 2 - \frac{1}{2}\ln {n}.$ In §8 (pp. 12-14) the result for $m$ positive terms followed by $n$ negative terms is shown to have sum $\ln 2 + \frac{1}{2}\ln \frac{m}{n}.$ Finally, §9 (p. 14) gives a summary of the result proved in §8, and §10 (pp. 14-15) appears to involve some type of concluding remarks. The only reference cited is in a footnote on p. 14, which directs the reader to see Aufsätze aus dem Gebiete der höhern Mathematik (Berlin, 1823), and no name appears anywhere except on the title page (in particular, neither Cauchy nor Dirichlet is mentioned). Some comments about Ohm and infinite series (but not the results he published in 1839) are given on pp. 30-31 of Cajori's 1888 paper History of infinite series.
[5] Ohm, Der Geist der Mathematischen Analysis und ihr Verhältniss zur Schule [The Spirit of Mathematical Analysis and Its Relationship to the Field], Erste Abhandlung [First Treatise], Duncker und Humblot (Berlin), 1842, xvi + 159 pages.
An English translation by Alexander John Ellis (1814-1890), titled The Spirit of Mathematical Analysis, and Its Relation to a Logical System, was published in 1843. After p. 103 of the English translation there are 3 pages (not numbered) that give some information about Ohm's published books. Ohm's 1839 essay De Nonnullis Seriebus Infinitis Summandis is not included. Incidentally, I highly recommend reading the Introduction (by Ohm) of the Ellis translation for an excellent account of many of the problems mathematicians were having at this time with interpreting various formal manipulations. The following is "[observation] (2)" on p. 56 [= pp. 87-88 of the 1842 German]: Now a convergent series has this value only by virtue of the law according to which its terms proceed in infinitum. Hence to prevent any doubt occurring concerning the true value of a convergent series, we must carefully enunciate the law according to which the terms are to be taken in infinitum. For example, from the same reciprocal terms of the natural numbers, viz. $$1, \; -\frac{1}{2}, \; +\frac{1}{3}, \; -\frac{1}{4}, \; +\frac{1}{5}, \; -\frac{1}{6}, \; +\frac{1}{7}, \; - \,\text{in inf.}$$ we may compose any number of numerical infinite series, which are all convergent but have all different values, each however having its own perfectly determinate value by virtue of the determinate law according to which it is constructed. The series $$1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \frac{1}{5} - \frac{1}{6} + \frac{1}{7} - \frac{1}{8} + \, \text{in inf.}$$ in which, if we take $2n$ terms, there are always as many positive as negative terms, has for its value log. nat. $2.$ The series $$1 + \frac{1}{3} - \frac{1}{2} + \frac{1}{5} + \frac{1}{7} - \frac{1}{4} + \frac{1}{9} + \frac{1}{11} - \frac{1}{6} + \, \text{in inf.}$$ in which, if we take the first $3n$ terms, $2n$ positive and only $n$ negative of the above terms follow one another (in their order) has for its value $\frac{3}{2}\,$log. nat. $2.$ The series $$1 - \frac{1}{2} - \frac{1}{4} + \frac{1}{3} - \frac{1}{6} - \frac{1}{8} + \frac{1}{5} - \frac{1}{10} - \frac{1}{12} + \frac{1}{7} - \, \text{in inf.}$$ in which, if we take the first $3n$ terms, we find $n$ of them positive and $2n$ negative, has for its value $\frac{1}{2}\,$log. nat. $2.$ And if we take $\mu$ of the above terms positive and $\nu$ negative, and then $\mu$ positive and $\nu$ negative, and so on, the value of the resulting numerical convergent series is $=\,$log. nat. $2 + \frac{1}{2}\,$log. nat.$\,\frac{\mu}{\nu},$ and therefore $=\,$log. nat. $2,$ which is that of the first series, when $\mu = \nu,$ but greater than that when $\mu > \nu$ and less when $\mu < \nu.$ For an outline of the method Ohm uses, see the top half of p. 818 of Cowen/Davidson/Kaufman (1980) below. Ohm is not mentioned in this 1980 paper, however.
[6] Victor Amédée Lebesgue (1791-1875), Sur la convergence des séries [On the convergence of series], Nouvelles Annales de Mathématiques (1) 4 (1845), 66-70.
For some biographical and bibliographical information about V. Lebesgue, see Poggendorff (1898, A-L, middle left column p. 784 to bottom left column p. 785). There appears to be no family/blood relationship between V. Lebesgue and Henri Lebesgue (known for the Lebesgue integral). (from bottom of p. 69 to end of the paper) [translated from French; math notation slightly modernized in some places] Proposition V. In a series containing negative terms, if we change the order of the terms, [then] we can $1^{\text o}$ change the sum without destroying the convergence; $2^{\text o}$ destroy the convergence, that is to say, render the series divergent instead of convergent. [Proof of] $1^{\text o}$ The series $$1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \cdots + \frac{1}{2n+1} - \frac{1}{2n+2},$$ [and] $$1 + \frac{1}{3} - \frac{1}{2} + \frac{1}{5} + \frac{1}{7} - \frac{1}{4} + \cdots + \frac{1}{4n+1} + \frac{1}{4n+3} - \frac{1}{2n+2},$$ are both convergent, because in the first the terms are decreasing, and it will be the same in the second by replacing $1 + \frac{1}{3}$ by $\frac{4}{3},$ [and] $\frac{1}{5} + \frac{1}{7}$ by $\frac{12}{35},$ etc. Moreover, if we take for general terms $\frac{1}{2n+1} - \frac{1}{2n+2} = \frac{1}{(2n+1)(2n+2)};$ [and] $\frac{1}{4n+1} + \frac{1}{4n+3} - \frac{1}{2n+2} = \frac{8n+5}{(4n+1)(4n+3)(2n+2)},$ [then] each term in the second series exceeds the corresponding term in the first, [and thus] we conclude that the sum of the first series is less than that of the second. [Proof of] $2^{\text o}$ The series $1 - \sqrt{\frac{1}{2}} + \sqrt{\frac{1}{3}} - \sqrt{\frac{1}{4}} + \cdots$ is convergent; but if instead of taking the negative terms $2$ by $2,$ we take them as above, $3$ by $3,$ [then] the series $1 + \sqrt{\frac{1}{3}} - \sqrt{\frac{1}{2}},\;$ $\sqrt{\frac{1}{5}} + \sqrt{\frac{1}{7}} - \sqrt{\frac{1}{4}},\;$ $\ldots,\;$ $\sqrt{\frac{1}{4n+1}} + \sqrt{\frac{1}{4n+3}} - \sqrt{\frac{1}{2n+2}}\;$ [a typo has been corrected], will be divergent. Cauchy's rule gives, assuming $n$ is very large, $\;\sqrt{\frac{1}{4n+1}} + \sqrt{\frac{1}{4n+3}} - \sqrt{\frac{1}{2n+2}} \; = \; \sqrt{\frac{1}{n}} - \sqrt{\frac{1}{2n}} \; = \; \frac{{\sqrt 2} - 1}{{\sqrt 2}{\sqrt n}},\;$ and $\;\frac{\ln \left(\frac{{\sqrt n}{\sqrt 2}}{{\sqrt 2} - 1}\right)}{\ln n} \; = \; \frac{1}{2} + \frac{\ln \left(\frac{\sqrt 2}{{\sqrt 2} - 1}\right)}{\ln n} \; < \; 1.$ These examples are taken from a memoir of Mr. Dirichlet, where it is established that any arithmetic progression contains infinitely many prime numbers, when the first term and the common difference are relatively prime.
[7] Charles-Adrien Choquet (1798-1880) and Mathias Mayer [Mayer-d'Almbert] (1786-1843), Traité Élémentaire d'Algèbre [Elementary Treatise on Algebra], 5th edition, Bachelier (Paris), 1849, xvi + 638 pages.
There exist 5 editions, published in 1832 (infinite series on pp. 198-201; nothing about rearrangements changing sums), 1836 (infinite series on pp. 244-247 and pp. 528-532; nothing about rearrangements changing sums), 1841 (infinite series on pp. 260-264 and pp. 578-583; nothing about rearrangements changing sums), 1845 (infinite series on pp. 260-264 and pp. 578-583; nothing about rearrangements changing sums), and [1849] (above; series on pp. 244-248 and pp. 583-588 and pp. 634-638; the possibility of rearrangements changing sums is discussed on pp. 634-638). In the first four editions the ordering of the authors on the title page differs from that of the 1849 5th edition in that in these earlier editions "Mayer" is listed first and "Choquet" is listed second. Because Mayer died in 1843, the 1845 4th edition and 1849 5th edition were by Choquet only. I do not know whether any corrections and additions to the last two editions may have been influenced by possible notes left by Mayer on suggestions for later editions, but I suspect the additional comments in the 5th edition about rearranging terms in the alternating harmonic series are entirely due to Choquet. Following the 1849 5th edition Choquet published two editions of Complément d'Algèbre (intended as a supplement to the 1849 5th edition), the 1st edition in 1851 (iv + 51 pages) and the 2nd edition in 1853 (iv + 63 pages), but neither of these includes any general discussions about infinite series. Finally, in 1856 Choquet published Traité d'Algèbre [Treatise on Algebra], Mallet-Bachelier (Paris), 1856, xvi + 551 pages. On pp. 548-551 of this 1856 book, Choquet discusses rearranging terms of a series. The 1856 version appears to be the same (word-for-word) as the 1849 version. Review of 5th edition in Nouvelles Annales de Mathématiques (1) 8 (1849), pp. 429-431 (in French). Some information about Choquet and Mayer and their books can be found here under the entry for "Urbain Le Verrier".
What follows is a translation of pp. 636-638 of the 1849 5th edition. 3. In order to show that, when convergence occurs only as a result of the signs, rearrangement of the terms can change the sum or render the series divergent, let us consider the series $$1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4} + \frac{1}{5} - \frac{1}{6} + ....$$ Let us take in succession two positive terms and one negative, in the following way $$1 + \frac{1}{3} - \frac{1}{2} + \frac{1}{5} + \frac{1}{7} - \frac{1}{4} + ....$$ This new series can be formed from the first, by adding to it that which results from dividing all its terms by $2.$ Thus, if one distributes the terms in groups of four terms, the $n^{\text{th}}$ group is $$\frac{1}{4n-3} - \frac{1}{4n-2} + \frac{1}{4n-1} - \frac{1}{4n};$$ after the division of all the terms by $2,$ [and then] grouping each term with its successor, the $n^{\text{th}}$ group is $$\frac{1}{4n-2} - \frac{1}{4n};$$ the sum of these two groups is $$\frac{1}{4n-3} + \frac{1}{4n-1} - \frac{1}{2n},$$ and if in succession [we use] $n=1,$ $=2,$ $=3,$ etc., the result is, successively, the groups of three terms of the series $1 + \frac{1}{3} - \frac{1}{2} +$ *etc. [Note: I will give a more explicit description. In what follows, $n$ is a positive integer (i.e. $n=1,$ $2,$ $3,\;\ldots).$ Let Series A be the series whose $n$'th term is the sum of the $(4n-3)$'th and $(4n-2)$'th and $(4n-1)$'th and $4n$'th terms of the first series (the alternating harmonic series). Let Series B be the series whose $n$'th term is $\frac{1}{2}$ times the $n$'th term of the first series. Let Series C be the series whose $n$'th term is the sum of the $(2n-1)$'th and $2n$'th terms of Series B. Let Series D be the series whose $n$'th term is the sum of the $n$'th term of Series A and the $n$'th term of Series C. Then the $n$'th term of Series D is $\frac{1}{4n-3} + \frac{1}{4n-1} - \frac{1}{2n},$ and this value is also equal to the sum of the $(3n-2)$'th and $(3n-2)$'th and $3n$'th terms of the new series (the rearranged alternating harmonic series).] Let $s_{2n}$ and $s_{4n}$ be the sum of the first $2n$ and of the first $4n$ terms of the first series; that of the first $2n$ terms of the series $\frac{1}{2} - \frac{1}{4} + \frac{1}{6} - \frac{1}{8} +$ etc. will be $\frac{1}{2}s_{2n};$ and the sum of the first $3n$ terms of the series obtained by rearrangement of the terms will be $s_{4n} + \frac{1}{2}s_{2n}.$ But, if we indefinitely increase the number $n,$ [then] the sums $s_{4n}$ and $s_{2n}$ converge to the same limit, which is $l\,2$ $[= {\ln 2}]$ $(n^{\text{o}}\;534)$ [= (article $534)].$ Therefore, $s_{4n} + \frac{1}{2}s_{2n}$ converges to $\frac{3}{2}l\,2.$ Thus the series $$1 + \frac{1}{3} - \frac{1}{2} + \frac{1}{5} + \frac{1}{7} - \frac{1}{4} + \cdots$$ has sum $\frac{3}{2}l\,2.$ 4. By another change in the order of the terms of the same series, we can obtain a divergent series. This would be if we alternately took groups of positive terms, then of negative terms, in which the number of terms increased by stages and indefinitely, in a manner that the value of each group was always greater than a given number, as the group below, for example, $$\frac{1}{n} + \frac{1}{n+2} + \frac{1}{n+4} + \cdots + \frac{1}{3n-2},$$ whose value is greater than $\frac{n}{3n-2}$ and therefore greater than $\frac{1}{3}.$ 5. By considering the convergent series $$1 - \frac{1}{\sqrt{2}} + \frac{1}{\sqrt{3}} - \frac{1}{\sqrt{4}} + \cdots,$$ we can even more easily derive a divergent series. It suffices to alternately take two positive terms then a negative term, as follows: $$1 + \frac{1}{\sqrt{3}} - \frac{1}{\sqrt{2}} + \frac{1}{\sqrt{5}} + \frac{1}{\sqrt{7}} - \frac{1}{\sqrt{4}} + ....$$ Indeed, if we put [In the first equation below have included a plus sign just after the term $-\frac{1}{\sqrt{4}}$ that did not appear in the original.] $$f(n) \;\; = \;\; 1 - \frac{1}{\sqrt{2}} + \frac{1}{\sqrt{3}} - \frac{1}{\sqrt{4}} + \cdots - \frac{1}{\sqrt{2n-2}} + \frac{1}{\sqrt{2n-1}} - \frac{1}{\sqrt{2n}},$$ $$F(n) \;\; = \;\; 1 + \frac{1}{\sqrt{3}} - \frac{1}{\sqrt{2}} + \cdots - \frac{1}{\sqrt{2n-2}} + \frac{1}{\sqrt{4n-3}} + \frac{1}{\sqrt{4n-1}} - \frac{1}{2n},$$ we have $$F(n) - f(n) \;=\; \frac{1}{\sqrt{2n+1}} + \frac{1}{\sqrt{2n+3}} + \cdots + \frac{1}{\sqrt{4n-1}}.$$ The second member of this equality is greater than $\frac{n}{\sqrt{4n-1}}$ and therefore greater than $\frac{1}{2}\sqrt{n}.$ It therefore tends to infinity along with $n.$ Therefore it is the same for $F(n)-f(n),$ and hence, for $F(n),$ since $f(n)$ is a finite quantity.