5
$\begingroup$

I want to know who derived $$\int_{0}^{\infty} \mathrm{e}^{-x^2}\, dx = \frac{\sqrt \pi}{2}$$ In school, our book mentioned that Euler proved this result. But on Math Stack Exchange, some people say that Laplace was the first person to derive this result. In Euler's book "Zur Theorie der komplexen Funktionen" he derives a more general integral and I think he knew how to use it to calculate the given integral.

I would be glad if someone could give a proper answer so I know who to give credit to.

$\endgroup$
5
$\begingroup$

While Nick R assumes in his answer that from Boyer's writing the formula is due to De Moivre, I think that is misleading and the first derivation of the formula you ask about really should be credited to Laplace.

De Moivre was working on the binomial approximation to the normal distribution, and his approximation involved a constant $B$ (I am taking that notation from De Moivre's paper at the York University site that Nick R links to in his answer). De Moivre could express $B$ as a series but he was not able to express $B$ in closed form. Stirling told him that $B = \sqrt{2\pi}$, without proof, and with this clue De Moivre was later able to derive that nice formula for $B$ using the Wallis product for $\pi$. The key point I want to make is that in none of this work (from the 1720s) was De Moivre directly using anything like an integral of $e^{-x^2}$ in order to make any calculations.

A better paper to look at on the York University website is here.

The first proof of the integral formula you ask about where the author used integrals was given by Laplace in the 1770s. He wrote the formula (after the change of variables $y = e^{-x^2}$) as $$ \int_0^1 \frac{dy}{\sqrt{-\log y}}\,dy = \sqrt{\pi} $$ and derived this from a formula for integrals due to Euler.

See here for many proofs of the integral formula you ask about. The eighth proof is Laplace's argument I allude to above and explains how it uses a result of Euler, and the tenth proof shows that this formula is equivalent to identifying the constant in Stirling's asymptotic estimate for $n!$ as $\sqrt{2\pi}$. The second proof is a much nicer alternate proof by Laplace that is a forerunner of the standard proof via squaring the integral and passing to polar coordinates; Laplace's alternate argument squares the integral and makes a different change of variables.

See the end of this for a discussion of how De Moivre's work on the binomial approximation to the normal distribution intersected with Stirling's work on Stirling's formula, and how Stirling found the constant $\sqrt{2\pi}$ in his formula.

$\endgroup$
  • $\begingroup$ @MrYouMath This answer makes the important point that De Moivre did not, apparently, express his formulation explicitly as an integral. Assuming this is correct, it is a point that appears to have been overlooked by Boyer (and myself). $\endgroup$ – Nick Jun 9 '16 at 16:25
  • $\begingroup$ @NickR, when Boyer writes that De Moivre worked with that formula, I believe he meant that De Moivre used something that today can be recognized as being equivalent to that formula. He was careful in his wording to say De Moivre worked with the formula rather than that he derived the formula. $\endgroup$ – KCd Jun 9 '16 at 18:20
  • $\begingroup$ Thanks. Yes, that is how I now read Boyer's text after reading your answer. I knew there was something about the wording used that wasn't quite on the mark, I just couldn't quite put my finger on it. $\endgroup$ – Nick Jun 9 '16 at 18:29
  • $\begingroup$ @KCd see also hsm.stackexchange.com/questions/7914/… $\endgroup$ – Francois Ziegler Nov 4 '18 at 16:36
1
$\begingroup$

According to Boyer's A History of Mathematics, Abraham De Moivre was the first to "work" with this formula, having obtained it in a privately printed pamphlet. Quoting Boyer :

De Moivre apparently was the first one to work with the probability formula $$\int_{0}^{\infty} \mathrm{e}^{-x^2}\, dx = \frac{\sqrt \pi}{2}$$ as a result that appeared unobtrusively in a privately printed pamphlet of 1733 entitled Approximatio ad summam terminorum binomii $(a+b)^n$ in seriem expansi. This work, representing the first appearance of the law of errors or the distribution curve, was translated by De Moirvre and included in the second edition (1738) of his Doctrine of Chances.

If there is a lack of clarity in Boyer's wording, the wikipedia page on De Moivre credits De Moivre as the author of the pamphlet. One assumes that De Moivre was therefore the first to derive it.

See also this paper on the York University site.

$\endgroup$
  • $\begingroup$ You know any resource to the derivation of De Moivre $\endgroup$ – MrYouMath Jun 9 '16 at 5:52
  • $\begingroup$ @MrYouMath I don't have anything at hand - this is all fairly new ground for me. However, KCd's answer below may provide some valuable additional information. $\endgroup$ – Nick Jun 9 '16 at 16:27

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.