# When were polynomial equations first factored?

The question pretty much says it all, though I have a specific example in mind. In the mid-1500s while working on his Ars Magna Cardano asked Tartaglia to solve the cubic $$x^3=9x+10$$. Using Tartaglia's formula results in having to take the square root of a negative number, which was undefined at the time; neither Tartaglia nor Cardano could solve the equation.

However, with a little work the above equation can be factored into $$(x+2)(x^2-2x-5)$$, and the three roots readily found using nothing more complicated than the quadratic formula which was known at the time. Clearly neither Tartaglia nor Cardano did this, as they had no solution to the original cubic.

All that aside, when was it realized that such higher-order equations could be factored?

• Well, for polynomials of degree > 4, the answer is "never" :-) – Carl Witthoft Dec 17 '18 at 13:23
• @CarlWitthoft: It is possible to factor many polynomials of high degree, we just can't do it for all such polynomials using radicals. – Rory Daulton Dec 18 '18 at 1:06
• This is good numerical counterexample that refutes the Cardano formula, where there were many more, In fact, I don't know why my comment in the below answer was utterly deleted, but in any case, the entire fundamental theorem of algebra and many more were easily refuted since long ago on sci. math,, Quora, and many deleted topics of mine strictly on Stalk Exchange many sections, where that doesn't alter the proven facts in my public published topics, link below: groups.google.com/forum/#!profile/sci.math/… – Bassam Karzeddin Jul 6 at 20:58
• The whole problem is basically to understand that the true radicals are strictly constructible numbers since they are supported only by the greatest theorem of Pythagoras about the truth of there existence, where other human manufactured radicals were supported only by human conclusions and no theorems but those were certainly proven as false conclusions, where the oldest root of the problem was one of the oldest impossible construction problems raised by the Greek's, where doubling the cube was never solved correctly by any means or tools since $\sqrt[3]{2}$ was proven as no number by me. – Bassam Karzeddin Jul 6 at 21:08