In William S. Gosset's The Probable Error of a Mean (JSTOR), he begins to derive the $t$ sampling distribution as follows.
Samples of $n$ individuals are drawn out of a population distributed normally...
If $s$ be the standard deviation found from a sample $x_1,x_2,...x_n$ (all these being measured from the mean of the population), then
$$ s^2 = \frac{S(x_1^2)}{n}-\left(\frac{S(x_1)}{n}\right)^2 = \frac{S(x_1^2)}{n} - \frac{S(x_1)^2}{n^2} - \frac{2S(x_1x_2)}{n^2} $$
And so on. What is the meaning of the $S$ notation, $S(x_1)$?
My first guess was summation, but summing over a scalar ($x_1$) doesn't mean much, and it's not clear how $S(x_1x_2)$ gets introduced.
Edit. @terry-s 's answer is correct, I just thought I'd add how Gosset's equation comes out of the typical sample standard deviation for anyone curious. The typical definition of standard deviation is (without Bessel's correction): $$ s^2 = \frac{1}{n} \sum (x_i-\bar x)^2 $$ For $$ \bar x = \frac{\sum x_i}{n} $$ If we expand, we have $$ (x_i-\bar x) = x_i^2 + \bar x ^2 - 2\bar x x_i $$ And thus the expression for $s^2$ becomes (after evaluating the sum of $\bar x$) $$ s^2 = \bar x^2 + \frac{\sum x_i^2}{n} - 2\bar x\frac{\sum x_i}{n} $$ And finally, by the definition of $\bar x$, the first and last terms on the right combine to give $-\bar x^2$, so $$ s^2 = \frac{\sum x_i^2}{n} - \bar x^2 $$ Or, more in line with Gosset's equation, this is $$ s^2 = \frac{\sum x_i^2}{n} - \left(\frac{\sum x_i}{n}\right)^2 $$ Which is identical to the equation Gosset starts with, assuming $S(x_1)=\sum x_i$. By the identity $$ \left(\sum x_i\right)^2 = \sum x_i^2 +2\sum_i \sum_{j=1}^{i-1} x_i x_j $$ we can expand the right-most term as $$ \left(\frac{\sum x_i}{n}\right)^2 = \frac{1}{n^2} \sum x_i^2 + \frac{2}{n^2} \sum_{i,\ j} x_i x_j $$ Where the double summation is to be performed for each $i$, taking $j$ from 1 to $i$, and this is what Gosset intended by $S(x_1 x_2)$.